For the reaction:
Cu. + 2Agar = Cu +24g, the
equilibrium constant KC is given by
Answers
Answered by
0
Answer:
Hey mate here is your answer...
Explanation:
Cu(s)+2Ag
2+
(aq)⟶Cu
2+
(aq)+2Ag(s)
E
o
=0.46V at 298K
logK
C
=
RT
nFE
o
=
0.059
2×0.46
K
C
=4×10
15
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