Question

For the reaction Fe2O3 + 3C02 + 2Fe + 3C02 the volume of carbon monoxide required to reduce one mole of ferric oxide is
А 67.2 dm
B 11.2 dm
С 22.4 dm
D 44.8 dm

Answer 1

Answer:

А 67.2 dm

Explanation:

Based on the given equation it is clear that 1 mole of Fe

2

O

3

i.e ferric oxide is reduced by 3 carbon monoxide.

1 mole of any compound occupies 22.4l of volume.

So, the volume of carbon monoxide required to reduce one mole of ferric oxide is =3×224.4dm

3

=67.2dm

3

.

Answer 2

$\huge\mathcal\red{Answer ✓}$

1 mol of Fe2O3 requires 3 mol of CO for its reduction i.e., 1 mol of Fe2O3 requires 3×22.4 litre or 67.2dm3CO to get itself reduced.

hope it will help you