Question

For the reaction h2(g) + f2 (g) ⇆ 2hf(g) ; the energy of activation of forward reaction is 208 kJ mol^-1. energy of activation of backward reaction is
A) 328 kJ mol^-1
B) 744 kJ mol^-1
C) 536 kJ mol^-1
D) None of the above

Answer 1

Answer:

Catalyst lower the E

af

to 20kJ/mole for forward Rxn then E

f

′

=20kJ/mol

We know catalyst decreases the activation energy equal amount in both directions:

E

b

′

=(120−60)=60kj/mol

E

b

′

E

b

=

60

120

=2.0