Question

For the reaction N O g NO g 2 4 2 2 if initially only 4 atm N O2 4 is present and at equilibrium, total pressure of equilibrium mixture is 6 atm then the value of KP is
1) 2 atm 2) 4 atm
3) 8 atm 4) 16 atm

Answer 1

Answer:

PNO2=0.64atm

PN2O4=0.05atm

Explanation:

For the first equilibrium, the total pressure is 1.1+0.28=1.38atm

The value of the equilibrium constant will be  Kp=PN2O4PNO22=0.281.12=4.32

For the second equilibrium, since the volume of the container is doubled, the total pressure will be one half i.e 21.38=0.69atm

The partial pressures of N2O4 and NO2 at equilibrium will be 0.69−x atm and x atm respectively.

The value of the equilibrium constant will be  Kp=PN2O4PNO22=0.69−xx2=4.32

PNO2=x=0.64atm and PN2O4=0.69−x=0.05atm