Question

For the reaction, N₂+ 3H₂➝ 2NH₃,d[NH₃]/dt =2 x 10⁻⁴ mol L⁻¹S⁻¹, the value of -d[H₂]/dt would be
(a)4х10⁻⁴mol L⁻¹S⁻¹
(b)6х10⁻⁴mol L⁻¹S⁻¹
(c)1х10⁻⁴mol L⁻¹S⁻¹
(d)3х10⁻⁴mol L⁻¹S⁻¹

Answer 1

Answer :- (c)1х10⁻⁴mol L⁻¹S⁻¹.

Answer 2

Hello Friend..!!

The answer of ur question is.!!

Option.D

Thank you.!!