Question

For the reaction,N2(g) + 3H2(g) 2NH3(g) if ∆[NH3]/∆t= 4x 10-8 molL-1 s^-1 .what is the value of - ∆[H2]/∆t ?

Answer 1

Answer:

Given that,

N2+3H2—>2NH3

∆[NH3]/∆t=4×10^-8molL^-1s^-1

From this,

-∆[H2]/∆t=3/2∆[NH3]/∆t

=3/2×4×10^-8

=6×10^-8molL^-1s^-2

Explanation:

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