for the reaction N2 (g)+ 3H2(g) gives 2 NH3 if delta [ NH3 ] /delta [t] = 410 ^-8 mol / liter^-1 sec^-1 what is. the rate of- delta [H2 ] / delta delta [t]?
Answers
Explanation:
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- Answer: Option B
Explanation:
Correct option is B
3×10 −4 molL −1 s −1
N 2 +3H 2 ⟶2NH 3
- Applying rate law.
3−1 dtd[H 2]
= 21
dt
d[NH 3 ]
- Now, given that
dt
d[NH 3 ]
=2×10 −4mol L −1 S −1
- Using above relation,
dt−d[H 2 ]
= 23
dt d[NH 3 ]
dt−d[H 2 ] = 23 ×2×10 −4 mol L −1 S −1
×2×10 −4 mol L −1 S −1
∴ dt−d[H 2 ] =3×10 −4 mol L −1S −1
=3×10 −4 mol L −1S −1