Question

For the reaction n2(g)+o2(g)2no(g)n2(g)+o2(g)2no(g), the equilibrium constant is k1.K1. The equilibrium constant is k2k2 for the reaction 2no(g)+o2(g)2no2(g).2no(g)+o2(g)2no2(g). What is equilibrium constant for the reaction? No2(g)12n2(g)+o2(g)no2(g)12n2(g)+o2(g)

Answer 1

N2 + O2--->2NO

K1=[NO]^2/[N2][O2]

2NO+O2--->2NO2

K2=[NO2]^2/[NO]^2*[O2]

Keeping the value of [NO]^2 in K2 as K1[N2][O2]

K2*K1=[NO2]/[N2][O2]^2

The given reaction is

NO2-->1/2N2 +O2

Keq=[N2]^(1/2) *[O2]/[NO2]=1/√(K1*K2)

Answer 2

Answer:

The equilibrium constant for the given reaction is $\frac{1}{K_1\times K_2}$.

Explanation:

$N_2(g)+O_2(g)\rightarrow 2NO(g)$...[1]

The equilibrium constant will given as:

$K_1=\frac{[NO]^2}{[N_2][O_2]}$

$2NO(g)+O_2(g)\rightarrow 2NO_2(g)$..[2]

The equilibrium constant will given as:

$K_2=\frac{[NO_2]^2}{[NO]^2[O_2]}$

Equilibrium constant for the reaction given in question: $K_3$

$NO_2(g)\rightarrow O_2(g)+\frac{1}{2}N_2(g)$

$2NO_2(g)\rightarrow 2O_2(g)+N_2(g)$

$K_3=\frac{[O_2]^2[N_2]}{[NO_2]^2}$

$K_3=\frac{[O_2]^2[N_2]}{[NO_2]^2}\frac{[NO]^2}{[NO]^2}$

$K_3=\frac{[N_2][O_2]}{[NO]^2}\times \frac{[NO]^2[O_2]}{[NO_2]^2}$

$K_3=\frac{1}{K_1\times K_2}$