Question

For the reaction n2o4(g)⇌2no2(g) the rate of disappearance of no2 will be

Answer 1

Our reaction is:
2NO₂ (g) ⇆ N₂O₄ (g)

Let p and q be constants for forward and backward reactions respectively

So,

The rate of disappearance of NO₂ is given by

-1/2 [ Δ |NO₂| / Δt ]

The rate of appearance of N₂O₄ is given by

Δ |N₂O₄| / Δt

As it is a reversible reaction, the rate of forward reaction is equal to rate of backward reaction, so
p = q
and
-1/2 [ Δ |NO₂| / Δt ] = Δ |N₂O₄| / Δt
So, we can say, the rate of disappearance of NO₂ is twice the rate of formation of N₂O₄.

Answer 2

Explanation:

just see the uploaded photo