Question

For the reaction, NO(g) + 21O2(g) NO2(g), the equilibrium constant is 2 × 10–2. Hence, its value for 4NO2 4NO + 2O2 is (a) 1.6 × 10–7 (b) 6.25 × 104 (c) 1.6 × 10–6 (d) 6.25 × 106​

Answer 1

Answer:

The given reaction is :-

2NO  

2

​  

(g)⇌2NO(g)+O  

2

​  

(g)

∴K  

C

​  

=  

[NO  

2

​  

]  

2

 

[NO]  

2

[O  

2

​  

]

​  

=2×10  

−6

→(I)

Now, 4NO(g)+2O  

2

​  

(g)⇌4NO  

2

​  

(g)

⇒K  

C

​  

 

′

 

=  

[NO]  

4

[O  

2

​  

]  

2

 

[NO  

2

​  

]  

4

 

​  

 

=(  

K  

C

​  

 

1

​  

)  

2

=(  

2×10  

−6

 

1

​  

)  

2

=2.5×10  

11

Explanation: