Question

For the reaction PCI, (g) + Cl2(g) =PC1s(9), the value of Kp at 250°C is 0.61 atm". The value of Kc at this temperature will be (A) 15 (mol/l) (B) 26 (mol/l)" (C) 35 (mol/l)" (D) 52 (mol /1) od Tlf we start​

Answer 1

Answer:

B

Explanation:

Kp=Kc(RT)^∆ng here ∆ng = -1 Kc = Kp × R × T

Kc=0.61×0.0821×523=26 mol/l

Answer 2

Answer:

B) 26 moles/L

Explanation:

Kp = Kc (RT)^n, n = Coefficient difference between gaseous reactants and products.

Kc = Kp/(RT)^n = 0.61/(0.082×523K)^-1 = 0.61×0.082×523 = 26.16 moles/L

hope this will help you