Question

For the reaction PCI5 ----> PCI3+Cl2 , the degree of dissociation varies inversely as the square root of pressure of the system. Supposing at constant temperature, If the volume is increased 16 times the intial volume, the degree of dissociation for this reaction will
become ? (1) 4 times (2) 1/4 times (3) 2 times (4) 1/2 times

Answer 1

Answer:

the above is sol of your que if any doubt comment.

Answer 2

For the reaction degree of dissociation becomes 4 times the initial amount.

The reaction is PCl5------>PCl3+Cl2

Let degree of dissociation be x

We know that at constant temperature according to Boyle's law we have

pressure of any gas at constant temperature is inversely proportional to the volume occupied by same gas at same temperature .

So we have pressure =1/volume......(1)

And according to the question x is inversely  proportional to square root of pressure .

x=(1/p)^1/2 so according to equation (1) p=1/v so

We have x=(1/p)^1/2 and p=1/v hence we have relation between degree of dissociation and volume is    x=(v)^1/2

Now initially degree of dissociation be x1 and volume be v1

now final volume be v2 and degree be x2

We know v2=16v1

Now x1/x2=(v1/v2)^1/2

Substituting values we have:--

x1/x2=(1/16)^1/2 so x2 =4x1

Hence degree of dissociation becomes 4 times it,s initial volume if volume increased 16 times.