Question

For the reaction :
$X_2O_4(l) \rightarrow 2XO_2(g)$
$\Delta U$ = 2.1 k cal, $\Delta S$ = 20 cal K⁻¹ at 300 K
Hence $\Delta G$ is:-
(a) 2.7 k cal
(b) – 2.7 k cal
(c) 9.3 k cal
(d) – 9.3 k cal

Answer 1

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✏ Option [A.] is Correct

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