For the reaction Ti(s)+2F2(g)→TiF4(s) compute the theoretical yield of the product (in grams) for each of the following initial amounts of reactants. Part A 5.0 g Ti, 5.0 g F2 Express your answer using two significant figures.
Answers
Answer:
The answer to your question is 8.2 g of TiF₄
Explanation:
Data
Theoretical yield = ?
mass of Ti = 5 g
mass of F₂ = 5 g
Balanced chemical reaction
Ti(s) + 2F₂ (g) ⇒ TiF₄(g)
Process
1.- Calculate the Molar mass of reactants and products
Ti = 48 g
2F₂ = 2( 19 x 2) = 76 g
TiF₄ = 48 + 76 = 124 g
2.- Calculate the limiting reactant
theoretical proportion Ti/F₂ = 48/76 = 0.63
experimental proportion Ti/F₂ = 5/5 = 1
Conclusion The limiting reactant is F₂ because the experimental proportion was lower than the theoretical proportion.
3.- Calculate the theoretical yield using the mass of F₂
76 g of F₂ --------------- 124 g of TiF₄
5 g of F₂ --------------- x
x = (5 x 124) / 76
x = 8.15 g of TiF₄