Question

For the reaction X + 2Y=3Z
If the entropy of X, Y and Z are 30, 30 and 20 J/mol-K and AH =-3 kJ/mol then the temperature of equilibrium condition will be :-

100 K
100°C
500 K
500
​

Answer 1

Explanation:

T= H/S

S= S(products)-S(reactants)