Question

For the reaction x mno4- + yc2o4^2+16h+___mn2+ +zco2 +8h 20. The X,y,z are

Answer 1

$\huge\underline\mathfrak\orange{Answer}$

Solution:-

The half equations of the reaction are

MnO−4→Mn2+

C2O2−4→CO2

The balanced half equations are

MnO−4+8H++5e−→Mn2++H2O

C2O2−4→2CO2+2e−

On equating number of electrons, we get

2MnO−4+16H++10e−→2Mn2−+8H2O

5C2O−4→10CO2+10e−

On adding both the equations, we get

2MnO−4+5C2O−4+16H+→2Mn2+

+2×5CO2+162H2O

Thus .x, y and z are 2, 5 and 16 respectively