Question

For the reactions
$A \rightleftharpoons B$; $K_c$ = 2
$B \rightleftharpoons C$; $K_c$ = 4
$C \rightleftharpoons D$; $K_c$ = 6
$K_c$ for the reaction $A \rightleftharpoons D$ is
(a) 2 × 4 × 6
(b) $\frac{2 x 4}{6}$
(c) 2 + 4 + 6
(d) $\frac{4 x 6}{2}$

Answer 1

d is a answer. ........