Question

for the real values of x ,the maximum value of x / x square -5x +9​

Answer 1

ANSWER

f(x)=4−6x−x

2

For critical points,

f

′

(x)=0

−6−2x=0

−2x=6

x=−3

For maxima/minima

f

′′

(x)=−2 (negative)

Hence at x=−3f(x) will have maxima

f(−3)=4−6×(−3)−(−3)

2

=4+18−9

f(−3)=13

Maximum value of f(x) is 13