Question

For the reversible reaction, $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)$ at 500°C, the value of $K_p$ is 1.44 x 10⁻⁵ when partial pressure is measured in atmospheres. The corresponding value of $K_c$, with concentration in mole litre⁻¹, is
(a) $\frac{1.44 x 10^{-5}}{(0.082 x 500)^{-2}}$
(b) $\frac{1.44 x 10^{-5}}{(8.314 x 773)^{-2}}$
(c) $\frac{1.44 x 10^{-5}}{(0.082 x 773)^2}$
(d) $\frac{1.44 x 10^{-5}}{(0.082 x 773)^{-2}}$

Answer 1

a) is absolutely correct

Answer 2

$\huge\bold{He¥\: Mate}$

$\textbf{\underline{HERE IS YOUR ANSWER}}}$

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$<b>$
➡️Correct Option -: D

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