Question

For the reversible vaporization of water at 100°C and 1 atm pressure, AG is equal to​

Answer 1

Answer:

Refer to the attachment

Hope it helps you

Answer 2

Answer:

ΔG for the reversible vaporization of water at 100°C and 1 atm pressure will be zero.

Explanation:

As given, reversible vaporation of water at 100°C and 1 atm

According to Gibb's equation,

ΔG = ΔH + TΔS

As the entropy change is always zero for the reversible process, ΔS=0

ΔG = ΔH + T*0

ΔG = ΔH

and as the temperature is constant then ΔH will be zero

ΔG = ΔH =0

Hence, the value of ΔG is equal to zero.