Math, asked by singhsamreet221, 8 months ago

For the rhombus ABCD ,the side AB =√29 units .B is at (-1,-2) and C is at (x,7) .Also x>0 then find x

Answers

Answered by rudhiyapremlata
3

Answer:

I don't know the answer sorry

Answered by velu14616
0

Answer:

x=1

Step-by-step explanation:

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Problem

For a rhombus ABCDABCDA, B, C, D, the side AB = \sqrt{29}AB=

29

A, B, equals, square root of, 29, end square root units.

BBB is at (-1,-2)(−1,−2)left parenthesis, minus, 1, comma, minus, 2, right parenthesis and CCC is at (x,-7)(x,−7)left parenthesis, x, comma, minus, 7, right parenthesis.

Also, x > 0x>0x, is greater than, 0.

Find xxx.

Hints

Strategy

All sides of a rhombus are equal.

So, BC = AB = \sqrt{29}BC=AB=

29

B, C, equals, A, B, equals, square root of, 29, end square root

We can write BCBCB, C in terms of xxx and solve the equation.

To find the length of sides using the vertices, we can use the distance formula.

What is the distance formula?

Finding BCBCB, C

Using distance formula, we get BC = \sqrt{(x + 1)^2 + 25}BC=

(x+1)

2

+25

B, C, equals, square root of, left parenthesis, x, plus, 1, right parenthesis, squared, plus, 25, end square root

Show me the steps.

We can equate this to \sqrt{29}

29

square root of, 29, end square root to find xxx.

Finding xxx

Equating BCBCB, C to \sqrt{29}

29

square root of, 29, end square root, we get x = 1x=1x, equals, 1 or x = -3x=−3x, equals, minus, 3.

Show me the steps.

As x > 0x>0x, is greater than, 0, we'll pick 111.

In conclusion,

x = 1x=1x, equals, 1.

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