Question

for the same angle of incidence in media L, M and N the angles of recreation are 45°, 35° and 15° respectively in which medium will the velocity of light be minimum? give reason for answer​

Answer 1

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Answer 2

Given:

For the same angle of incidence in media L, M and N the angles of recreation are 45°, 35° and 15° respectively.

To find:

Which medium will have minimum velocity of light?

Calculation:

Let angle of incidence be i and the light enters from air into the respective media.

Applying Snell's Law in general:

$\therefore \: 1 \times \sin(i) = \mu \times \sin(r)$

$\implies \: \mu = \dfrac{ \sin(i) }{ \sin(r) }$

$\implies \: \mu \propto \dfrac{ 1 }{ \sin(r) }$

Now, we know that with higher angle, the value of sin increases.

• Since medium L has max angle r , value of $\mu$ will be least.

• Since medium N has min angle r , value of $\mu$ will be max.

$\therefore \: \mu_{N} > \mu_{M} > \mu_{L}$

Again, refractory index is written as :

$\therefore \: \mu = \dfrac{v_{vacuum} }{ v_{medium}}$

$\implies \: \mu \propto \dfrac{1 }{ v_{medium}}$

$\implies \:v_{medium} \propto \dfrac{1}{ \mu}$

So, higher the refractive index , lower will be velocity of light in the medium.

Since , medium N has max refractive index, velocity of light will be minimum.