Question

For the same circuit above, find V_CV
C
​ and enter it into the space below without units. (V_CV
C
​ is the voltage across the top element, not the voltage at the point c in the circuit.)

Answer 1

Answer:

A) Phase difference between V and I is

2

π

. So the device can be a capacitor.

B) Curve A represents power P=VI , where the amplitude is equivalent to the multiplication of amplitudes of V and I curve. Curve B is sine curve and represents voltage and curve C is a cosine curve representing the current.

Full cycle of the graph consist of two positive and two negative symmetrical area. So the average power consumed in the circuit is zero.

C) The AC impedance of a capacitor is known as Reactance and as we are dealing with capacitor circuits, more commonly called Capacitive Reactance, X

C

. Graph shows variation of capacitive reactance with frequency.

D) V=V

0

sinωt

Q=CV

Where C is capacitance.

I=

dt

dQ

=C

dt

dV

=CV

0

ωcosωt

Thus there is a

2

π

phase difference between current and voltage.