Question

For the school assembly, the students are made to stand so that the number of rows is equal to the number of students in each row. Find how many more students to be added to 3974 students to keep the number of students and rows equal

Answer 1

Answer:

122

Step-by-step explanation:

Students are standing in a manner that the number of rows and the number of students in each row are the same.

So, we can say that the number of rows and the number of columns are the same for the arrangement i.e. it is an n×n matrix where the number of students is n².

Let us assume that n²=3974, ⇒ n= 63.04

Hence, 3974 number is not a perfect square as n is always a positive integer.

If we want to add more students to 3974 to make it a perfect square, then assume that n=64, then n²= 4096.

Therefore, to make 3974 a perfect square, we have to add (4096-3974)= 122 more students to the group and then only we can arrange them in the n×n matrix i.e. there will be 64 rows and in each row, there will be 64 students. (Answer)

Answer 2

Answer:

5184 students

Step-by-step explanation:

number of rows - 72

number of students in each row - 72

Total = 72 × 72

= 5184 students

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