For the sequence √2,√8,√18,√32,....,find a15
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Answer:a[n] = 6 + 6*n + (sum(4*(n-1)) from n = 0 to n = n)
it works like this:
a[0] = 6 + 0 + (-4) = 2
a[1] = 6 + 6 + (-4 + 0) = 8
a[2] = 6 + 12 + (-4 + 0 + 4) = 18
a[3] = 6 + 18 + (-4 + 0 + 4 + 8) = 32
a[4] = 6 + 24 + (-4 + 0 + 4 + 8 + 12) = 50
it works for all of the numbers listed.
n has to be greater than or equal to 0
when n = 0, 4 * (n-1) becomes 4 * (-1) = -4
when n = 1, 4 * (n-1) becomes 4 * (0) = 0
Step-by-step explanation:
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