Question

for the series parallel arrangement shown in the below figure find (a) the supply current (b) the current flowing through each resistor and (c) the P.D across each resistor​

Answer 1

The answer ✏ will be :-)

a) 25 A.

b) I through :

R1 = 25 A;

R2 = 6.25 A;

R3 = 18.75A;

R4 = 25 A;

c)P.d through :

R1 = 62.5 V;

R2 = 37.5V;

R3 = 37.5 V;

R4 = 100V;

Explanation:

Given ;

total volt = 200 V;

R1 = 2.5 ohm; R2 = 6 ohm;R3 = 2 ohm; R4 = 4 ohm;

Let's take Rp = R2 + R3 for the purpose of understanding;

a) Total effective resistance = R1 + Rp + R4; (i)

Here, 1/Rp = 1/R2 + 1/R3;

1/Rp = 1/6 + 1/2;

1/Rp = 4/6;

Rp = 6/4 = 3/2 = 1.5 ohm;

Hence, put all the value on the equation (i);

= 2.5 + 1.5 + 4;

= 4 + 4;

= 8 ohm;

According to Ohm's law;

I = V / R;

Now put the required value;

I = 200 / 8;

= 25 A;

b) Since, R1 , Rp, R4 are in series. Hence, current will be constant;

Therefore, I through R1 = 25 A;

Now, Rp is the parallel combination of resistor R2 and R3;

If we take Rp in series (which, indeed, is in series when we take whole R3 and R2 as a single resistor) with R1 and R2, then I through Rp = 25 A

Now, p.d through Rp = I × Rp ;

= 25 ×1.5;

= 37.5 V;

Now, P.d. in R2 and R3 will be constant since they are in parallel combination.

Now, current through R2 = V / R2;

= 37.5 / 6;

= 6.25 A;

And, current through R3 = V / R3;

= 37.5 / 2;

= 18.75 A;

Since, R4 is also in series hence, current through R4 = 25 A;

∴ I through :

R1 = 25 A;

R2 = 6.25 A;

R3 = 18.75 A;

R4 = 25 A;

c) P.d. through R1 = I × R1;

= 25 ×2.5;

= 62.5 V;

Here, Rp is the parallel combination of R1 and R2;

And, I in R2 = 6.25 A;

and, I in R3 = 18.75 A;

Hence, P.d. through R2 = I in R2 ×R2;

= 6.25 × 6;

= 37.5 V.

and P.d. through R 3 = I in R3 × R3;

= 18.75 ×2;

= 37.5 V.

(This shows that Potential difference in R2 and R3 is same just because they are in parallel combination.)

Now, P.d through R4 = I × R4;

= 25 × 4;

= 100 V;

∴ P.d through :

R1 = 62.5 V;

Rp = R2 = 37.5V;

R3 = 37.5 V;

R4 = 100V;

That's all.

Answer 2

Answer:

The supply current will be the static current, plus switching current, plus (the sum of all the) load currents delivered to the loads through the outputs. ... If you do that, and don't connect too low an impedance to the outputs, the device will limit its current draw well below the absolute maximum suppply current limit.