Question

for the situation shown in figure find the final position of BLOCK from the point c on BC, mu=0.4​

Answer 1

Explanation:

where is figure but I'll try it myself

Consider that both the blocks are displaced by x each then, by energy method

21k(2x)2+21mv2+21mv2= constant

mv2+2kx2= constant

Taking derivative of both sides wrt t

m×2vdtdN+2k×2xdtdx=0

ma+2kx=0 [dtdv=a;dtdx=v]

⇒a=−(m2k)x [a=−ω2x] i.e., it is SHM

⇒ω=m2k

Thus, time period (T)=2π2km

[T=ω2π].

Answer 2

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