Question

for the system A(g) +2b(g) = c(g) the equilibrium concentration are. (A) 0.06mole/litre (B) 0.12mole/litre (C) 0.216 mole/litre. The k (eq) for the reaction is?​

Answer 1

Answer:

for the system A(g) +2B(g) = C(g) the equilibrium concentration are. (A) 0.06mole/litre (B) 0.12mole/litre (C) 0.216 mole/litre. The k (eq) for the reaction is 250

Explanation:

For the reaction A(g) +2B(g) = C(g)

K= $\frac{[C]}{[A] [B]^{2} } =\frac{0.216}{(0.06)(0.12)^{2} } =250$