Question

for the system A(g) +2b(g) = c(g) the equilibrium concentration are. (A) 0.06mole/litre (B) 0.12mole/litre (C) 0.216 mole/litre. The k (eq) for the reaction is

Answer 1

k(eq) =(c)/((a)*(b^2))
=0.216/0.06*0.12^2
=0.216/0.06*0.0144
=0.216/0.000864
=216*10^-3/864*10^-6
=250
it is option (a)