Question

for the two circle is x^2+y^2=16and x^2+y^2-2y=0​

Answer 1

Answer:

ANSWER

Circle S1 is x

2

+y

2

=16

Circle S2 is x

2

+y

2

−2y=0

Centre C1 is C

1

(0,0) and radius R

1

=4

Centre C2 is C

2

(0,1) and radius R

2

=1

Distance between Centres is C

1

C

2

=1

Since C

1

C

2

<∣R

2

−R

1

∣

Circle S2 is completely inside S1

⟹ No common tangents