Question

For the two equations Kx - 3y-1=0 and (4 - k) x - y + 1=0 would have no solutions, find the value of k​

Answer 1

Answer:

value of k = 3

Step-by-step explanation:

no solution occurs when

a1/a2 = b1/b2 does not = c1/c2

so A/q we will put the respective value in the above equation

k/(4-k) = -3/-1

k/(4-k) = 3/1

by cross multiplication

k = 3(4-k)

k = 12-3k

k+3k = 12

4k = 12

k = 12/4

k = 3