Question

for the value of k 5x-7y-5=0 and 2x+ky-1=0​

Answer 1

Answer:

hope it help.................

Answer 2

/* Question is incomplete , It must be like this */

$Compare \: given \: pair \: of \: equations : \\5x-7y-5=0 \: and \: 2x+ky-1 = 0 \:with \\a_{1}x+b_{1}y+c_{1} = 0 \: and \: a_{2}x+b_{2}y+c_{2} = 0 ,we \: get$

$a_{1} = 5 , b_{1} = -7 , c_{1} = -5 ; \\a_{2} = 2 , b_{2} = k \: and \: c_{2} = -1$

/* we know that , */

$If \: the \: equations \: have\\ unique \: solution \:then ,$

$\pink{\frac{a_{1}}{a_{2}} \neq \frac{b_{1}}{b_{2}}}$

$\implies \frac{5}{2} \neq \frac{-7}{k}$

$\implies k \neq (-7) \times \frac{2}{5}$

$\implies k \neq \frac{-14}{5}$

Therefore.,

$\red{ The \: value \: of \: k }\green { \neq \frac{-14}{5}}$

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