Question

For the value of k if kx(x-2)+6=0 has two equal roots

Answer 1

Please see the attachment

Answer 2

Answer:

Given the equation kx(x - 2) + 6 = 0 Or,  kx² - 2kx + 6 = 0 ; has equal roots.

Therefore ,

Dicriminant , "D" = 0

Or, b² - 4ac = 0         ------------ A.

putting the values from the equation in A. ;

=> (-2kx)² - 4 (kx²)(6) = 0

=> 4k²x² = 24kx²

=> k = 6

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