for the value of nth term to A.P.'s 63,65,67 and 3,10,17... equal?
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Tn1=tn2
63+(n-1)*(2) = 3+(n-1)*(7)
63+2n+-2= 3+7n-7
61+4 = 5n
n =13
63+(n-1)*(2) = 3+(n-1)*(7)
63+2n+-2= 3+7n-7
61+4 = 5n
n =13
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