For the vectors ⃗ = (3, 1, 0), ⃗ = (2, 2, 3) and ⃗ = (−1, 2, 1), ⃗ ⊥ ( ⃗ + ⃗), then = ____. (a) 8 (b) 4 (c) 1/ 8 (d) 1/ 4
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Answer:
B
T
=
∣
∣
∣
∣
∣
∣
∣
∣
−1
1
2
0
2
−1
∣
∣
∣
∣
∣
∣
∣
∣
So, AB
T
=
∣
∣
∣
∣
∣
∣
3
−1
−1
2
0
3
∣
∣
∣
∣
∣
∣
×
∣
∣
∣
∣
∣
∣
∣
∣
−1
1
2
0
2
−1
∣
∣
∣
∣
∣
∣
∣
∣
=
∣
∣
∣
∣
∣
∣
3(−1)−1(1)+0(2)
−1(−1)+2(1)+3(2)
3(0)−1(2)+0(−1)
−1(0)+2(2)+3(−1)
∣
∣
∣
∣
∣
∣
=
∣
∣
∣
∣
∣
∣
−4
9
−2
1
∣
∣
∣
∣
∣
∣
And (AB
T
)
T
=
∣
∣
∣
∣
∣
∣
−4
−2
9
1
∣
∣
∣
∣
∣
∣
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