Question

For There are 15th term in an AP.3, 5,7...
term?
find last​

Answer 1

Answer:

31

Step-by-step explanation:

Here

n=15;

AP=3,5,7

therefore, a= 3

d= 5-3 =2. (d is the common difference and is equal to a2-a1)

therefore

last term= a+(n-1)D

= 3+(15-1)2

= 3+28

= 31 Ans