for theta =30° find sin2theta=2sinthetacostheta
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Answered by
4
Step-by-step explanation:
LHS
sin2 30
=sin60
=√3/2
RHS
2sin 30cos 30
=2×1/2 ×√3/2
=√3/2
HENCE PROVED......
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Answered by
0
Step-by-step explanation:
first consider LHS
sin2∅
by placing 30° in the place of ∅
we get sin2∅ = sin2(30°) = sin60°
sin 60° = √3/2
now consider RHS
2sin∅cos∅
by placing 30° in the place of ∅
we get 2×sin30°×cos30°
2×1/2×√3/2
2,1/2 cancel out
remaining √3/2
∴LHS=RHS
HENCE PROVED
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