For this you draw a right angle (90 degrees, perpendicular) triangle, with the two adjacent legs at 3N and 4N respectively. Then the crosswise leg (hypotenuse, opposite side) will have a length of the square root of 3N squared plus 4N squared, i.e. 5N. [3x3 + 4x4 = 9+16 = 25 = 5x5]. One more thing: The angle of the resultant will be the vector sum of the two forces; that angle will be the inverse tangent of 3/4 or 0.75.... hmm, look it up online or on my calculator: 36.86989765 degrees (about 37 degrees) or 0.64350111 radians. There are usually several ways to solve most problems like this; the result should be the same, but it can be expressed using different units.
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Answer:
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Explanation:
For this you draw a right angle (90 degrees, perpendicular) triangle, with the two adjacent legs at 3N and 4N respectively. Then the crosswise leg (hypotenuse, opposite side) will have a length of the square root of 3N squared plus 4N squared, i.e. 5N. [3x3 + 4x4 = 9+16 = 25 = 5x5]. One more thing: The angle of the resultant will be the vector sum of the two forces; that angle will be the inverse tangent of 3/4 or 0.75.... hmm, look it up online or on my calculator: 36.86989765 degrees (about 37 degrees) or 0.64350111 radians. There are usually several ways to solve most problems like this; the result should be the same, but it can be expressed using different units.