Question

For three finite sets, n(A) = 34, n(B) = 41, n(C) =
52, n(AnB) = 15, n(BnC) = 19, n(CnA) = 12.
A possible value of n(A U BU C) is
(1) 97
(3) 98
(2) 93
(4) 100​

Answer 1

Answer:92

Step-by-step explanation:

Answer 2

Answer:

that's the answer.

hope it helps...