Question

for three moles of monatomic gas the value of CP/CV is?​

Answer 1

Given:

3 moles of monoatomic gas.

To find:

Value of Cp/Cv ?

Calculation:

• Irrespective of the number of moles of an ideal gas, the value of Cp/Cv will always remain same for that type of gas.

For monoatomic gas:

$C_{V}= \dfrac{3R}{2} \: and \: C_{P} = \dfrac{5R}{2}$

So, the required value will be :

$\therefore \: \dfrac{C_{P}}{C_{V}} = \dfrac{ \dfrac{5}{2} }{ \dfrac{3}{2} }$

$\implies\: \dfrac{C_{P}}{C_{V}} = \dfrac{ 5 }{ 3 }$

$\implies\: \dfrac{C_{P}}{C_{V}} = 1.67$

So, value of Cp/Cv is 1.67