Question

For three resistors connected in series, prove that the equivalent resistance is equal to the sum of the individual resistances.(physics class 10)​(urgent please tell)

Answer 1

I hope this helps (θ‿θ)

Answer 2

Explanation:

By Ohm’s law, the potential differences across the three resistors will be,

V1=IR1,V2=IR2,V3=IR3

Rs be the equivalent resistance of the series combination, then on applying a potential difference V across it, the same current I must flow through it. 

Therefore,

V=IRs

But V=V1+V2+V3

∴,IRs=IR1+IR2+IR3

⟹IRs=I(R1+R2+R3)

⟹Rs=R1+R2+R3

Laws of resistances in series:

(i) Current through each resistance is same

(ii) Total voltage across the combination = sum of the voltage drops

(iii) Voltage drop across any resistor is proportional to its resistance

(iv) Equivalent resistance = sum of the individual resistances

(v) Equivalent resistance is larger than the largest individual resistance.