for trapezium given below find its area
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2
Answer:
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Answered by
1
Answer:
Trapezium Area.
∴CD=MN=12cm
∴AM=NB=
2
20−12
4cm
→ As shown in figure
△AMD using
pythagoras theorem
AD
2
=AM
2
+MD
2
∴(10)
2
=(4)
2
+MD
2
∴MD
2
=(10)
2
−(4)
2
=100−16
∴MD
2
=84
∴MD=
84
→ Area of trapezium
A=(
2
AB+CD
)× perpendicular distance
=(
2
20+12
)×MD
=
2
32
×
84
=16×
84
A=146.64cm
2
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