Question

for triangle ABC,PROVD THAT SEC A+B/2=COSEC B/2​

Answer 1

Answer:

Given ABC is a triangle,so

A+B+C=180

A+B/2+C/2=90

A+B/2=(90-C/2)

Applying secant on both sides

sec(A+B/2)=sec(90-c/2)

sec(A+B/2)= cosec c/2. (as 90 is odd sec changes to cosec)

hence proved.

Step-by-step explanation:

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