Question

for triangle abc prove that b²-c²/a²*sin2a+c²-a²/b²*sin2b+a²-b²/c²*sin2c=0​

Answer 1

Answer:

for triangle abc prove that b²-c²/a²*sin2a+c²-a²/b²*sin2b+a²-b²/c²*sin2c=0

for triangle abc prove that b²-c²/a²*sin2a+c²-a²/b²*sin2b+a²-b²/c²*sin2c=0