Question

for triangle ABC; prove that: sec a + c / 2 = cosec B / 2.​

Answer 1

Answer:

Answer

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InnocentBachiNo1

Since A, B and C are interior angles.

So, A+B+C=180° [Angle Sum Property]

A+B = 180°- C

A+B/2 = 90°- C/2

Now, sec (A+B/2)

= sec (90°- C/2)

=cosec C/2