Question

For triangle ABC prove that
sec (A+C)/2 =cosecB/2​

Answer 1

Step-by-step explanation:

Given A,B,C are the interior angles of △ABC

⟹A+B+C=180

∘

⟹A+B=180

∘

−C

LHS=cosec(

2

A+B

)

=cosec(

2

180

∘

−C

)

=cosec(90

∘

−

2

C

)

=sec

2

C

=RHS

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