Question

For triangle ABC, prove that :
sec A+C = cosec B
------- -----
2 2
​

Answer 1

Answer:

Step-by-step explanation:

[ angle sum property]

Dividing both sides by 2 <a + <b + <c / 2

= 180/2 <b + <c /2

= 90 - <c/2 Sec<b + <c /2

= sec 90- <a/2. Sec<b + <c/2

= cosec<a/2.

Hence proved

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