Question

For triangle ABC, show that: sin(A+B)/2=cosC/2​

Answer 1

Step-by-step explanation:

In Triangle

A+,B+C=180

divide by2

A/2+B/2+C/2=90

A/2+B/2=90-C/2

sin(A+B/2)=sin(90-c/2)

sin (A+B)/2=cos C/2

Answer 2

Now since

A+B+C=180

(A+B+C)/2=90°

(A+B)/2=90°−C/2

sin(A+B)/2=sin(90°−C/2). . . Taking sines on both sides

sin(A+B)/2=cos(C/2) 

Proof done

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