For two arbitrary events A and B. show that P(A+B)= P(A)+ P(B)-P(AB)
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For arbitrary events A, B, we have
P(A∪B)=P(A)+P(B)−P(A∩B). ...(1)
Since probability of an event is a non-negative quantity, equation (1) gives
P(A)+P(B)−P(A∩B)≥0
or P(A)+P(B)≥P(A∩B)
or P(A∩B)≤P(A)+P(B).
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