for two concentric circle of radius 25 cm and 7 cm the chord of the larger circle that touches the smaller circle find the length
Answers
Answered by
21
Answer:
AB=?
In ΔOAC –
OA² = α² + AC²
25² = 7² + AC²
AC² = 625 − 49 = 576
AC=24
Similarly
In ΔOCB –
OB² = OC² + BC²
25² = 7² + BC²
BC² = 625 − 49
BC = 24
AB = AC+CB
AB = 48cm
Answered by
2
Step-by-step explanation:
AB=?
In ΔOAC –
OA² = α² + AC²
25² = 7² + AC²
AC² = 625 − 49 = 576
AC=24
Similarly
In ΔOCB –
OB² = OC² + BC²
25² = 7² + BC²
BC² = 625 − 49
BC = 24
AB = AC+CB
AB = 48cm
I hope you get help.
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